C code to covert each digits of a number in English word

C code to covert each digits of a number in English word

Convert digits to words in c

#include<stdio.h>

int main(){

    int number,i=0,j,digit;

    char * word[1000];

    printf("Enter any integer: ");

    scanf("%d",&number);

    while(number){

    digit = number %10;

    number = number /10;

         switch(digit){

             case 0: word[i++] = "zero"; break;

             case 1: word[i++] = "one"; break;

             case 2: word[i++] = "two"; break;

             case 3: word[i++] = "three"; break;

             case 4: word[i++] = "four"; break;

             case 5: word[i++] = "five"; break;

             case 6: word[i++] = "six"; break;

             case 7: word[i++] = "seven"; break;

             case 8: word[i++] = "eight"; break;

             case 9: word[i++] = "nine"; break;

         }

    }

   

    for(j=i-1;j>=0;j--){

         printf("%s ",word[j]);

    }

    return 0;

}

Sample output:

Enter any integer: 23451208

two three four five one two zero eight