Pascal triangle in c without using array

1. Pascal triangle in c without using array

2. C code to print Pascal triangle

3. Simple c program for Pascal triangle

4. C program to generate Pascal triangle

5. Pascal triangle program in c language

6. C program to print Pascal triangle using for loop

#include<stdio.h>

long fact(int);

int main(){

    int line,i,j;

    printf("Enter the no. of lines: ");

    scanf("%d",&line);

    for(i=0;i<line;i++){

         for(j=0;j<line-i-1;j++)

             printf(" ");

         for(j=0;j<=i;j++)

             printf("%ld ",fact(i)/(fact(j)*fact(i-j)));

         printf("\n");

    }

    return 0;

}

long fact(int num){

    long f=1;

    int i=1;

    while(i<=num){

         f=f*i;

         i++;

  }

  return f;

 }

Sample output:

Enter the no. of lines: 8

       1

      1 1

     1 2 1

    1 3 3 1

   1 4 6 4 1

  1 5 10 10 5 1

 1 6 15 20 15 6 1

1 7 21 35 35 21 7 1

c program to print Floyd’s triangle

1. Write a c program to print Floyd’s triangle

2. C program to display Floyd’s triangle

3. How to print Floyd’s triangle in c

#include<stdio.h>

int main(){

  int i,j,r,k=1;

  printf("Enter the range: ");

  scanf("%d",&r);

  printf("FLOYD'S TRIANGLE\n\n");

  for(i=1;i<=r;i++){

      for(j=1;j<=i;j++,k++)

           printf(" %d",k);

      printf("\n");

  }

  return 0;

}

Sample output:

Enter the range: 10

FLOYD'S TRIANGLE

 1

 2 3

 4 5 6

 7 8 9 10

 11 12 13 14 15

 16 17 18 19 20 21

 22 23 24 25 26 27 28

 29 30 31 32 33 34 35 36

 37 38 39 40 41 42 43 44 45

 46 47 48 49 50 51 52 53 54 55

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What is Floyd’s triangle?

Definition of floyd's triangle:

Floyd's triangle is a right angled-triangle using the natural numbers. Examples of floyd's triangle:

Example 1:

1

2 3

4 5 6

7 8 9 10

Example 2:

1

2   3

4   5   6

7   8   9   10

11  12  13  14  15

16  17  18  19  20 21

C code to covert each digits of a number in English word

C code to covert each digits of a number in English word

Convert digits to words in c

#include<stdio.h>

int main(){

    int number,i=0,j,digit;

    char * word[1000];

    printf("Enter any integer: ");

    scanf("%d",&number);

    while(number){

    digit = number %10;

    number = number /10;

         switch(digit){

             case 0: word[i++] = "zero"; break;

             case 1: word[i++] = "one"; break;

             case 2: word[i++] = "two"; break;

             case 3: word[i++] = "three"; break;

             case 4: word[i++] = "four"; break;

             case 5: word[i++] = "five"; break;

             case 6: word[i++] = "six"; break;

             case 7: word[i++] = "seven"; break;

             case 8: word[i++] = "eight"; break;

             case 9: word[i++] = "nine"; break;

         }

    }

   

    for(j=i-1;j>=0;j--){

         printf("%s ",word[j]);

    }

    return 0;

}

Sample output:

Enter any integer: 23451208

two three four five one two zero eight

Convert numbers to roman numerals in c

Convert numbers to roman numerals in c

#include<stdio.h>

void predigits(char c1,char c2);

void postdigits(char c,int n);

char roman_Number[1000];

int i=0;

int main(){

    int j;

    long int number;

   

    printf("Enter any natural number: ");

    scanf("%d",&number);

   

    if(number <= 0){

         printf("Invalid number");

         return 0;

    }

    while(number != 0){

         if(number >= 1000){

             postdigits('M',number/1000);

             number = number - (number/1000) * 1000;

         }

         else if(number >=500){

             if(number < (500 + 4 * 100)){

                 postdigits('D',number/500);

                 number = number - (number/500) * 500;

             }

             else{

                 predigits('C','M');

                 number = number - (1000-100);

             }

         }

         else if(number >=100){

             if(number < (100 + 3 * 100)){

                 postdigits('C',number/100);

                 number = number - (number/100) * 100;

             }

             else{

                 predigits('L','D');

                 number = number - (500-100);

             }

         }

         else if(number >=50){

             if(number < (50 + 4 * 10)){

                 postdigits('L',number/50);

                 number = number - (number/50) * 50;

             }

             else{

                 predigits('X','C');

                 number = number - (100-10);

             }

         }

         else if(number >=10){

             if(number < (10 + 3 * 10)){

                 postdigits('X',number/10);

                 number = number - (number/10) * 10;

             }

             else{

                 predigits('X','L');

                 number = number - (50-10);

             }

         }

         else if(number >=5){

             if(number < (5 + 4 * 1)){

                 postdigits('V',number/5);

                 number = number - (number/5) * 5;

             }

             else{

                 predigits('I','X');

                 number = number - (10-1);

             }

         }

         else if(number >=1){

             if(number < 4){

                 postdigits('I',number/1);

                 number = number - (number/1) * 1;

             }

             else{

                 predigits('I','V');

                 number = number - (5-1);

             }

         }

    }

    printf("Roman number will be: ");

    for(j=0;j<i;j++)

         printf("%c",roman_Number[j]);

    return 0;

}

void predigits(char c1,char c2){

    roman_Number[i++] = c1;

    roman_Number[i++] = c2;

}

void postdigits(char c,int n){

    int j;

    for(j=0;j<n;j++)

         roman_Number[i++] = c;

   

}

Sample output:

Enter any natural number: 87

Roman number will be: LXXXVII

C code for roman numbers to English numbers

C code for roman numbers to English numbers

#include<stdio.h>

#include<string.h>

int digitValue(char);

int main(){

    char roman_Number[1000];

    int i=0;

    long int number =0;

   

    printf("Enter any roman number (Valid digits are I, V, X, L, C, D, M):  \n");

    scanf("%s",roman_Number);

   

    while(roman_Number[i]){

        

         if(digitValue(roman_Number[i]) < 0){

             printf("Invalid roman digit : %c",roman_Number[i]);

             return 0;

         }

            

         if((strlen(roman_Number) -i) > 2){

             if(digitValue(roman_Number[i]) < digitValue(roman_Number[i+2])){

                 printf("Invalid roman number");

                 return 0;

             }

         }

         if(digitValue(roman_Number[i]) >= digitValue(roman_Number[i+1]))

             number = number + digitValue(roman_Number[i]);

         else{

             number = number + (digitValue(roman_Number[i+1]) - digitValue(roman_Number[i]));

             i++;

         }

         i++;

    }

        

    printf("Its decimal value is : %ld",number);

   

    return 0;

}

int digitValue(char c){

    int value=0;

    switch(c){

         case 'I': value = 1; break;

         case 'V': value = 5; break;

         case 'X': value = 10; break;

         case 'L': value = 50; break;

         case 'C': value = 100; break;

         case 'D': value = 500; break;

         case 'M': value = 1000; break;

         case '\0': value = 0; break;

         default: value = -1; 

    }

    return value;

}

Sample output:

Enter any roman number (Valid digits are I, V, X, L, C, D, M):

XVII

Its decimal value is: 17

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Alogrithm: